Add additionial proof needed for proseminar
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@ -3967,9 +3967,12 @@ Wir haben eine echte Verallgemeinerung.
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\im(\alpha^\dagger) = \im(\alpha^\dagger \circ \alpha)
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\end{aligned}
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\end{equation}
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\tl UE\br\,:
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$\ker(\alpha) \subseteq \ker(\alpha^\dagger \circ \alpha) \subseteq \ker(\alpha \circ \alpha^\dagger
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\circ \alpha) = \ker(\alpha) \implies \ker(\alpha) = \ker(\alpha \circ \alpha^\dagger \circ \alpha)$
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$\ker(\alpha) \subseteq \ker(\alpha^\dagger \circ \alpha) \subseteq
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\ker(\alpha \circ \alpha^\dagger \circ \alpha)
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= \ker(\alpha) \implies \ker(\alpha) = \ker(\alpha^\dagger \circ \alpha)$
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$\im(\alpha) \subseteq \im(\alpha \circ \alpha^\dagger) \subseteq
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\im(\alpha \circ \alpha^\dagger \circ \alpha) = \im(\alpha) \implies
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\im(\alpha) = \im(\alpha \circ \alpha^\dagger)$
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\item $\nu := \alpha^\dagger \circ \alpha$ erfüllt $\nu \circ \nu$ und ist selbstadjungiert
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? für $\nu' := \alpha \circ \alpha^\dagger$ \\
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$\implies \underbrace{\ker(\nu)}_{=\ker(\alpha)} \bot \im(\nu)$
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