87 lines
2.2 KiB
Python
87 lines
2.2 KiB
Python
"""
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Google (News)
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@website https://news.google.com
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@provide-api no
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@using-api no
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@results HTML
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@stable no
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@parse url, title, content, publishedDate
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"""
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from lxml import html
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from searx.engines.google import _fetch_supported_languages, supported_languages_url
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from searx.url_utils import urlencode
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from searx.utils import match_language
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# search-url
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categories = ['news']
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paging = True
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language_support = True
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safesearch = True
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time_range_support = True
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number_of_results = 10
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search_url = 'https://www.google.com/search'\
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'?{query}'\
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'&tbm=nws'\
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'&gws_rd=cr'\
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'&{search_options}'
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time_range_attr = "qdr:{range}"
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time_range_dict = {'day': 'd',
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'week': 'w',
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'month': 'm',
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'year': 'y'}
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# do search-request
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def request(query, params):
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search_options = {
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'start': (params['pageno'] - 1) * number_of_results
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}
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if params['time_range'] in time_range_dict:
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search_options['tbs'] = time_range_attr.format(range=time_range_dict[params['time_range']])
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if safesearch and params['safesearch']:
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search_options['safe'] = 'on'
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params['url'] = search_url.format(query=urlencode({'q': query}),
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search_options=urlencode(search_options))
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if params['language'] != 'all':
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language = match_language(params['language'], supported_languages, language_aliases).split('-')[0]
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if language:
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params['url'] += '&hl=' + language
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return params
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# get response from search-request
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def response(resp):
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results = []
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dom = html.fromstring(resp.text)
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# parse results
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for result in dom.xpath('//div[@class="g"]|//div[@class="g _cy"]'):
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try:
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r = {
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'url': result.xpath('.//a[@class="l lLrAF"]')[0].attrib.get("href"),
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'title': ''.join(result.xpath('.//a[@class="l lLrAF"]//text()')),
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'content': ''.join(result.xpath('.//div[@class="st"]//text()')),
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}
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except:
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continue
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imgs = result.xpath('.//img/@src')
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if len(imgs) and not imgs[0].startswith('data'):
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r['img_src'] = imgs[0]
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results.append(r)
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# return results
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return results
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