libremiami-search/searx/query.py

131 lines
4.4 KiB
Python

#!/usr/bin/env python
'''
searx is free software: you can redistribute it and/or modify
it under the terms of the GNU Affero General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
searx is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU Affero General Public License for more details.
You should have received a copy of the GNU Affero General Public License
along with searx. If not, see < http://www.gnu.org/licenses/ >.
(C) 2014 by Thomas Pointhuber, <thomas.pointhuber@gmx.at>
'''
from searx.languages import language_codes
from searx.engines import (
categories, engines, engine_shortcuts
)
import string
import re
class Query(object):
"""parse query"""
def __init__(self, query, blocked_engines):
self.query = query
self.blocked_engines = []
if blocked_engines:
self.blocked_engines = blocked_engines
self.query_parts = []
self.engines = []
self.languages = []
# parse query, if tags are set, which
# change the serch engine or search-language
def parse_query(self):
self.query_parts = []
# split query, including whitespaces
raw_query_parts = re.split(r'(\s+)', self.query)
parse_next = True
for query_part in raw_query_parts:
if not parse_next:
self.query_parts[-1] += query_part
continue
parse_next = False
# part does only contain spaces, skip
if query_part.isspace()\
or query_part == '':
parse_next = True
self.query_parts.append(query_part)
continue
# this force a language
if query_part[0] == ':':
lang = query_part[1:].lower()
# check if any language-code is equal with
# declared language-codes
for lc in language_codes:
lang_id, lang_name, country = map(str.lower, lc)
# if correct language-code is found
# set it as new search-language
if lang == lang_id\
or lang_id.startswith(lang)\
or lang == lang_name\
or lang == country:
parse_next = True
self.languages.append(lang)
break
# this force a engine or category
if query_part[0] == '!':
prefix = query_part[1:].replace('_', ' ')
# check if prefix is equal with engine shortcut
if prefix in engine_shortcuts\
and not engine_shortcuts[prefix] in self.blocked_engines:
parse_next = True
self.engines.append({'category': 'none',
'name': engine_shortcuts[prefix]})
# check if prefix is equal with engine name
elif prefix in engines\
and prefix not in self.blocked_engines:
parse_next = True
self.engines.append({'category': 'none',
'name': prefix})
# check if prefix is equal with categorie name
elif prefix in categories:
# using all engines for that search, which
# are declared under that categorie name
parse_next = True
self.engines.extend({'category': prefix,
'name': engine.name}
for engine in categories[prefix]
if engine not in self.blocked_engines)
# append query part to query_part list
self.query_parts.append(query_part)
def changeSearchQuery(self, search_query):
if len(self.query_parts):
self.query_parts[-1] = search_query
else:
self.query_parts.append(search_query)
def getSearchQuery(self):
if len(self.query_parts):
return self.query_parts[-1]
else:
return ''
def getFullQuery(self):
# get full querry including whitespaces
return string.join(self.query_parts, '')