82 lines
1.9 KiB
Python
82 lines
1.9 KiB
Python
## 1x (Images)
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#
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# @website http://1x.com/
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# @provide-api no
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#
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# @using-api no
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# @results HTML
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# @stable no (HTML can change)
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# @parse url, title, thumbnail, img_src, content
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from urllib import urlencode
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from urlparse import urljoin
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from lxml import html
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import string
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import re
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# engine dependent config
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categories = ['images']
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paging = False
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# search-url
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base_url = 'http://1x.com'
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search_url = base_url+'/backend/search.php?{query}'
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# do search-request
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def request(query, params):
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params['url'] = search_url.format(query=urlencode({'q': query}))
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return params
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# get response from search-request
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def response(resp):
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results = []
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# get links from result-text
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results_parts = re.split(r'(</a>|<a)', resp.text)
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cur_element = ''
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# iterate over link parts
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for result_part in results_parts:
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# processed start and end of link
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if result_part == '<a':
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cur_element = result_part
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continue
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elif result_part != '</a>':
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cur_element += result_part
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continue
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cur_element += result_part
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# fix xml-error
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cur_element = string.replace(cur_element, '"></a>', '"/></a>')
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dom = html.fromstring(cur_element)
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link = dom.xpath('//a')[0]
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url = urljoin(base_url, link.attrib.get('href'))
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title = link.attrib.get('title', '')
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thumbnail_src = urljoin(base_url, link.xpath('.//img')[0].attrib['src'])
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# TODO: get image with higher resolution
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img_src = thumbnail_src
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# check if url is showing to a photo
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if '/photo/' not in url:
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continue
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# append result
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results.append({'url': url,
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'title': title,
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'img_src': img_src,
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'content': '',
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'thumbnail_src': thumbnail_src,
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'template': 'images.html'})
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# return results
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return results
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