sched: yield fix
fix yield bugs due to the current-not-in-rbtree changes: the task is not in the rbtree so rbtree-removal is a no-no. [ From: Srivatsa Vaddagiri <vatsa@linux.vnet.ibm.com>: build fix. ] also, nice code size reduction: kernel/sched.o: text data bss dec hex filename 38323 3506 24 41853 a37d sched.o.before 38236 3506 24 41766 a326 sched.o.after Signed-off-by: Ingo Molnar <mingo@elte.hu> Signed-off-by: Dmitry Adamushko <dmitry.adamushko@gmail.com> Reviewed-by: Thomas Gleixner <tglx@linutronix.de>
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1 changed files with 5 additions and 20 deletions
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@ -739,9 +739,7 @@ static void dequeue_task_fair(struct rq *rq, struct task_struct *p, int sleep)
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static void yield_task_fair(struct rq *rq)
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{
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struct cfs_rq *cfs_rq = task_cfs_rq(rq->curr);
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struct rb_node **link = &cfs_rq->tasks_timeline.rb_node;
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struct sched_entity *rightmost, *se = &rq->curr->se;
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struct rb_node *parent;
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/*
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* Are we the only task in the tree?
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@ -755,39 +753,26 @@ static void yield_task_fair(struct rq *rq)
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* Dequeue and enqueue the task to update its
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* position within the tree:
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*/
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dequeue_entity(cfs_rq, se, 0);
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enqueue_entity(cfs_rq, se, 0);
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update_curr(cfs_rq);
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return;
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}
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/*
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* Find the rightmost entry in the rbtree:
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*/
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do {
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parent = *link;
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link = &parent->rb_right;
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} while (*link);
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rightmost = rb_entry(parent, struct sched_entity, run_node);
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rightmost = __pick_last_entity(cfs_rq);
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/*
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* Already in the rightmost position?
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*/
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if (unlikely(rightmost == se))
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if (unlikely(rightmost->vruntime < se->vruntime))
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return;
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/*
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* Minimally necessary key value to be last in the tree:
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* Upon rescheduling, sched_class::put_prev_task() will place
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* 'current' within the tree based on its new key value.
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*/
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se->vruntime = rightmost->vruntime + 1;
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if (cfs_rq->rb_leftmost == &se->run_node)
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cfs_rq->rb_leftmost = rb_next(&se->run_node);
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/*
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* Relink the task to the rightmost position:
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*/
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rb_erase(&se->run_node, &cfs_rq->tasks_timeline);
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rb_link_node(&se->run_node, parent, link);
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rb_insert_color(&se->run_node, &cfs_rq->tasks_timeline);
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}
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/*
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