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[IA64] remove redundant display of free swap space in show_mem()

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show_mem() has no need to print the amount of free swap space manually because
show_free_areas() does this already and is called by the former.

The two outputs only differ in text formatting:

  printk("Free swap  = %lukB\n", ...);
  printk("Free swap:       %6ldkB\n", ...);

Signed-off-by: Johannes Weiner <hannes@saeurebad.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Tony Luck <tony.luck@intel.com>
This commit is contained in:
Johannes Weiner 2008-03-28 14:27:04 -07:00 committed by Tony Luck
parent b34eb53cdc
commit 734bc367b4
2 changed files with 0 additions and 4 deletions
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2
arch/ia64/mm/contig.c
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@ -45,8 +45,6 @@ void show_mem(void)
printk(KERN_INFO "Mem-info:\n");
show_free_areas();
printk(KERN_INFO "Free swap: %6ldkB\n",
nr_swap_pages<<(PAGE_SHIFT-10));
printk(KERN_INFO "Node memory in pages:\n");
for_each_online_pgdat(pgdat) {
unsigned long present;

2
arch/ia64/mm/discontig.c
View file

@ -522,8 +522,6 @@ void show_mem(void)
printk(KERN_INFO "Mem-info:\n");
show_free_areas();
printk(KERN_INFO "Free swap: %6ldkB\n",
nr_swap_pages<<(PAGE_SHIFT-10));
printk(KERN_INFO "Node memory in pages:\n");
for_each_online_pgdat(pgdat) {
unsigned long present;