UBIFS: fix available blocks count
Take into account that 2 eraseblocks are never available because they are reserved for the index. This gives more realistic count of FS blocks. To avoid future confusions like this, introduce a constant. Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>
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3 changed files with 13 additions and 9 deletions
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@ -280,13 +280,8 @@ int ubifs_calc_min_idx_lebs(struct ubifs_info *c)
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* extra LEB to compensate.
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*/
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ret += 1;
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/*
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* At present the index needs at least 2 LEBs: one for the index head
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* and one for in-the-gaps method (which currently does not cater for
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* the index head and so excludes it from consideration).
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*/
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if (ret < 2)
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ret = 2;
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if (ret < MIN_INDEX_LEBS)
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ret = MIN_INDEX_LEBS;
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return ret;
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}
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@ -695,9 +695,10 @@ static int init_constants_late(struct ubifs_info *c)
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* necessary to report something for the 'statfs()' call.
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*
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* Subtract the LEB reserved for GC, the LEB which is reserved for
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* deletions, and assume only one journal head is available.
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* deletions, minimum LEBs for the index, and assume only one journal
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* head is available.
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*/
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tmp64 = c->main_lebs - 2 - c->jhead_cnt + 1;
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tmp64 = c->main_lebs - 1 - 1 - MIN_INDEX_LEBS - c->jhead_cnt + 1;
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tmp64 *= (uint64_t)c->leb_size - c->leb_overhead;
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tmp64 = ubifs_reported_space(c, tmp64);
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c->block_cnt = tmp64 >> UBIFS_BLOCK_SHIFT;
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@ -63,6 +63,14 @@
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#define SQNUM_WARN_WATERMARK 0xFFFFFFFF00000000ULL
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#define SQNUM_WATERMARK 0xFFFFFFFFFF000000ULL
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/*
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* Minimum amount of LEBs reserved for the index. At present the index needs at
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* least 2 LEBs: one for the index head and one for in-the-gaps method (which
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* currently does not cater for the index head and so excludes it from
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* consideration).
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*/
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#define MIN_INDEX_LEBS 2
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/* Minimum amount of data UBIFS writes to the flash */
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#define MIN_WRITE_SZ (UBIFS_DATA_NODE_SZ + 8)
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