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simejo 2021-09-24 00:29:16 +02:00
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\usepackage{mathtools}
\usepackage{amssymb}
\usepackage{pgfplots}
\title{Analyse 1 - TD 1 \\ NON CORRIGÉ}
\author{Timéo Pochin}
@ -92,4 +93,83 @@
\subsection*{k)}
\section*{Exercice 2}
\[
f:x\mapsto ax+b
\]
\begin{align}
& \big(|f(-1)|=3\big)\land\big(|f(2)=2|\big) \nonumber \\
\iff\quad & (|b-a|=3)\land(|2a+b|=2) \nonumber \\
\iff\quad & (b-a=3\lor b-a=-3)\land(2a+b=2\lor 2a+b=-2) \nonumber \\
\iff\quad & (b-a=3\land 2a+b=2) \nonumber \\
\lor & (b-a=3\land 2a+b=-2) \nonumber \\
\lor & (b-a=-3\land 2a+b=2) \nonumber \\
\lor & (b-a=-3\land 2a+b=-2) \nonumber
\end{align}
\begin{align}
& b-a=3\land 2a+b=2 \nonumber \\
\iff\quad & 3a=-1\land 3b=8 \nonumber \\
\iff\quad & a=-\frac{1}{3}\land b=\frac{8}{3} \nonumber \\
\end{align}
\begin{align}
& b-a=3\land 2a+b=-2 \nonumber \\
\iff\quad & 3a=-5\land 3b=4 \nonumber \\
\iff\quad & a=-\frac{5}{3}\land b=\frac{4}{3} \nonumber \\
\end{align}
\begin{align}
& b-a=-3\land 2a+b=2 \nonumber \\
\iff\quad & 3a=5\land 3b=-4 \nonumber \\
\iff\quad & a=\frac{5}{3}\land b=-\frac{4}{3} \nonumber \\
\end{align}
\begin{align}
& b-a=-3\land 2a+b=-2 \nonumber \\
\iff\quad & 3a=1\land 3b=-8 \nonumber \\
\iff\quad & a=\frac{1}{3}\land b=-\frac{8}{3} \nonumber \\
\end{align}
Donc
\[
(a,b)\in
\left\{
\left(-\frac{1}{3},\frac{8}{3}\right),
\left(-\frac{5}{3},\frac{4}{3}\right),
\left(\frac{5}{3},-\frac{4}{3}\right),
\left(\frac{1}{3},-\frac{8}{3}\right)
\right\}
\]
\begin{tikzpicture}
\begin{axis}[
xmin = -5, xmax = 5,
ymin = -5, ymax = 5,
axis x line = middle,
axis y line = middle,
xtick distance = 1,
ytick distance = 1,
grid = both,
minor tick num = 5,
major grid style = {lightgray},
minor grid style = {lightgray!25},
width = \textwidth,
height = \textwidth
]
\addplot[
color = black
]{-(1/3)*x+(8/3)};
\addplot[
color = black
]{-(5/3)*x+(4/3)};
\addplot[
color = black
]{(1/3)*x-(8/3)};
\addplot[
color = black
]{(5/3)*x-(4/3)};
\end{axis}
\end{tikzpicture}
\end{document}

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