ex. 2
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\usepackage{mathtools}
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\usepackage{amssymb}
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\usepackage{pgfplots}
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\title{Analyse 1 - TD 1 \\ NON CORRIGÉ}
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\author{Timéo Pochin}
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\subsection*{k)}
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\section*{Exercice 2}
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\[
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f:x\mapsto ax+b
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\]
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\begin{align}
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& \big(|f(-1)|=3\big)\land\big(|f(2)=2|\big) \nonumber \\
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\iff\quad & (|b-a|=3)\land(|2a+b|=2) \nonumber \\
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\iff\quad & (b-a=3\lor b-a=-3)\land(2a+b=2\lor 2a+b=-2) \nonumber \\
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\iff\quad & (b-a=3\land 2a+b=2) \nonumber \\
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\lor & (b-a=3\land 2a+b=-2) \nonumber \\
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\lor & (b-a=-3\land 2a+b=2) \nonumber \\
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\lor & (b-a=-3\land 2a+b=-2) \nonumber
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\end{align}
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\begin{align}
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& b-a=3\land 2a+b=2 \nonumber \\
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\iff\quad & 3a=-1\land 3b=8 \nonumber \\
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\iff\quad & a=-\frac{1}{3}\land b=\frac{8}{3} \nonumber \\
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\end{align}
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\begin{align}
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& b-a=3\land 2a+b=-2 \nonumber \\
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\iff\quad & 3a=-5\land 3b=4 \nonumber \\
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\iff\quad & a=-\frac{5}{3}\land b=\frac{4}{3} \nonumber \\
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\end{align}
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\begin{align}
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& b-a=-3\land 2a+b=2 \nonumber \\
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\iff\quad & 3a=5\land 3b=-4 \nonumber \\
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\iff\quad & a=\frac{5}{3}\land b=-\frac{4}{3} \nonumber \\
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\end{align}
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\begin{align}
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& b-a=-3\land 2a+b=-2 \nonumber \\
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\iff\quad & 3a=1\land 3b=-8 \nonumber \\
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\iff\quad & a=\frac{1}{3}\land b=-\frac{8}{3} \nonumber \\
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\end{align}
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Donc
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\[
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(a,b)\in
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\left\{
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\left(-\frac{1}{3},\frac{8}{3}\right),
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\left(-\frac{5}{3},\frac{4}{3}\right),
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\left(\frac{5}{3},-\frac{4}{3}\right),
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\left(\frac{1}{3},-\frac{8}{3}\right)
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\right\}
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\]
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\begin{tikzpicture}
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\begin{axis}[
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xmin = -5, xmax = 5,
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ymin = -5, ymax = 5,
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axis x line = middle,
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axis y line = middle,
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xtick distance = 1,
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ytick distance = 1,
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grid = both,
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minor tick num = 5,
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major grid style = {lightgray},
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minor grid style = {lightgray!25},
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width = \textwidth,
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height = \textwidth
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]
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\addplot[
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color = black
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]{-(1/3)*x+(8/3)};
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\addplot[
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color = black
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]{-(5/3)*x+(4/3)};
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\addplot[
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color = black
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]{(1/3)*x-(8/3)};
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\addplot[
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color = black
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]{(5/3)*x-(4/3)};
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\end{axis}
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\end{tikzpicture}
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\end{document}
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